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Who can help me decrypt

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I need a sha 512 decrypted can anyone do it for me?
 
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13644a1534d66081042fb3d69775ee7c

there is the thing i need decrypted
 
Pyth0n

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That isn't a sha512 hash. It's only 32 characters in length, so it's probably md5.
 
Zorg93

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Try http://cmd5.org/ it has everything.
lol that site is pathetic, you cant decrypt hashes, especially not sha512, its more hash inputs and hope to get the same output or lookup a table. but because of the size of a sha512 hash you would need a table with 1.34x10^154 different hashes to find a match. To put it in other words, if every single computer on earth was working together, the sun would still burn out way before one would be able to create an input to match the output, provided the initial input was secure enough. Long story short, all those websites are fake
 
lowpro

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lol that site is pathetic, you cant decrypt hashes, especially not sha512, its more hash inputs and hope to get the same output or lookup a table. but because of the size of a sha512 hash you would need a table with 1.34x10^154 different hashes to find a match. To put it in other words, if every single computer on earth was working together, the sun would still burn out way before one would be able to create an input to match the output, provided the initial input was secure enough. Long story short, all those websites are fake
Unless a computer got lucky and got it on the first try :wink:
 
Zorg93

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Unless a computer got lucky and got it on the first try :wink:
computers dont work on luck, then would attempt to crack by using a starting value, lets say a, then cycling through possibilities for 1 char e.g. a, b, c, d. then move onto 2 chars and go aa, ab, ac, ad...ba, bb, bc etc etc. that way they know they get everypossibility, but considering there are 255 possible characters for a password(exluding the null char) then removing things like CR, LF. say there a 200 different characters that can be inputted with a keyboard. and say the password length is known at 20(very secure) chars long, thats still 1.04 x10^46, and that still would only work if you knew the hash and the hashing algorithm used
 
lowpro

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computers dont work on luck, then would attempt to crack by using a starting value, lets say a, then cycling through possibilities for 1 char e.g. a, b, c, d. then move onto 2 chars and go aa, ab, ac, ad...ba, bb, bc etc etc. that way they know they get everypossibility, but considering there are 255 possible characters for a password(exluding the null char) then removing things like CR, LF. say there a 200 different characters that can be inputted with a keyboard. and say the password length is known at 20(very secure) chars long, thats still 1.04 x10^46, and that still would only work if you knew the hash and the hashing algorithm used
What you could do (I think, not my field of study), is start by choosing random passwords, and they must start at length 20. If that were the case they could get 1.04x10^46 lucky and get it on the first try :biggrin:
 
Zorg93

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What you could do (I think, not my field of study), is start by choosing random passwords, and they must start at length 20. If that were the case they could get 1.04x10^46 lucky and get it on the first try :biggrin:
problem with doing random is they would repeat chances and not cover all options
 
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problem with doing random is they would repeat chances and not cover all options
You could have a set of all possible hashes, then have every hash tested removed from that set. This would enable a random-ish test method; however, it would be computationally less efficient, but perhaps statistically more efficient.

Still, it would take forever.
 
Zorg93

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You could have a set of all possible hashes, then have every hash tested removed from that set. This would enable a random-ish test method; however, it would be computationally less efficient, but perhaps statistically more efficient.

Still, it would take forever.
yeah, you cant really decrypt something that is known for being a one way algorithm
 
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